What is the power output of an electric motor
that lifts a 2.0-kilogram block 15 meters
vertically in 6.0 seconds?
(1) 5.0 J (3) 49 J
(2) 5.0 W (4) 49 W
Mass of the block = 2.0 kg Value of gravity = 9.81 m/s^2 Distance upto which the mass is lifted = 15 meters Time taken to lift the mass of the block = 6.0 seconds Now we already know Work Done = Mass * Gravity * Distance = 2 * 9.81 * 15 = 294 Joules Then Power Output = Work Done/Time = 294/6 = 49 Watts So the power output of the electric motor is 49 watts.The correct option among all the options given in the question is option "4".