bonnyanidreb
bonnyanidreb
01-06-2015
Mathematics
contestada
h(x)=2x²+x-10
2x²+x-10=0
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AyaZ
AyaZ
01-06-2015
[tex]2 x^{2} +x-10=0 \\ \\ (2x+5)(x-2)=0 \\ \\ x_{1} =- \frac{5}{2} \\ x_{2} =2[/tex]
Answer Link
hunaifirst
hunaifirst
01-06-2015
h(x)=2x2+x-10
2x²+x-10=0
(2x+5)(x-2)
x=-5/2
x=2
1)
h(x)=2x²+x-10
h(-5/2)= 2(-25/4)+[-5/2]-10
h(-5/2)=-25
2).
h(x)=2x²+x-10
h(2)=2(2)²+2-10
h(2)=8+(-8)
h(2)=0
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