camoo11
camoo11
03-04-2017
Mathematics
contestada
what's the solution to 20+2x<5x+17-3x
Respuesta :
Аноним
Аноним
03-04-2017
1 Simplify 5x+17-3x to
2x+17
20+2x<2x+17
2 Cancel 2x on both sides.
20<17
3 Since
20<17
is false, there is no solution
No solution. :)
I hope this helps you understand! :D
Have a great day by the way.
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ItsLeviosaaa
ItsLeviosaaa
03-04-2017
Treat it like an equation, you'll do a simple two-step rearrangement:
20+2x < 5x +17-3x -> 20+2x < 2x+17 -> 3+2x < 2x -> 3 < 0x. Now at this point in solving we run into a problem... nothing times 0 can be greater than 3, so this is undefined
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