ChiziteluN653005 ChiziteluN653005
  • 03-11-2022
  • Mathematics
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Twice a number, decreased by 4, is at least 12. Which of the following is a solution?8576

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SapphiraL235077 SapphiraL235077
  • 03-11-2022

Answer:

8

Explanation:

Let the number = n

Twice the number decreased by 4:

[tex]2n-4[/tex]

The phrase 'at least' means the expression above can either be equal to or greater than 12.

Thus, the given statement as inequality is:

[tex]2n-4\geq12[/tex]

We then solve the inequality for n.

[tex]\begin{gathered} \text{ Add 4 to both sides} \\ 2n-4+4\geq12+4 \\ 2n\geq16 \\ \text{ Divide both sides by 2} \\ \frac{2n}{2}\geq\frac{16}{2} \\ n\geq8 \\ \implies n=(8,9,10,\cdots) \end{gathered}[/tex]

The number that is a solution is 8.

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