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01-11-2021
Mathematics

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Prove 8 sin^3 x cos x = 2 sin 2x - sin 4x

Prove 8 sin3 x cos x 2 sin 2x sin 4x class=

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lynnkc2000 lynnkc2000

01-11-2021

Answer:

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Step-by-step explanation:

[tex]8sin^{3} x*cos x \\= 4sin^{2} x*2sin x cos x\\= 4sin^{2} x* sin 2x\\ = 2sin 2x*(2sin^{2} x)\\ = 2sin 2x*(1-(1-2sin^{2} x))\\ = 2sin 2x*(1-cos 2x)\\ = 2sin 2x - 2sin2x*cos 2x\\ = 2sin 2x - sin 4x[/tex]

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