Answer:
Answer: x is 2.28 and 0.22
Step-by-step explanation:
• From the quadratic formular of general equation ax² + bx + c = 0
[tex]x = \frac{ - b± \sqrt{ {b}^{2} - 4ac } }{2a} \\ [/tex]
• By comparison with equation given:
a » 2, b » -5, and c » 1
• substitute:
[tex]x = \frac{ - ( - 5)± \sqrt{ {( - 5)}^{2} - (4 \times 2 \times 1) } }{(2 \times 2)} \\ \\ x = \frac{5± \sqrt{17} }{4} \\ \\ x = 2.28 \: \: and \: \: 0.22[/tex]
