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  • 02-06-2021
  • Mathematics
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A parabola with the equation y=a(x-b)^2+c has a minimum of (-2,1) and a y-intercept of 5. What are the values of a, b and c? What are the x-intercepts?

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stayoriginal0616 stayoriginal0616
  • 02-06-2021

Answer: 3^15

Step-by-step explanation: carry the one to the 5 divide by the third and multiply the fractions , find the mean ( average ) of the mode and square that to find your a b and c values

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