03-09-2016
Mathematics

contestada

2x/x2-25=10/x2-25 - 4/x+5

Respuesta :

03-09-2016

Hello,

x²-25≠0==>x≠5 and x≠-5

[tex] \dfrac{2x}{x^2-25}= \dfrac{10}{x^2-25}- \dfrac{4}{x+5} \\ \dfrac{2x}{x^2-25}= \dfrac{10}{x^2-25}- \dfrac{4(x-5)}{(x+5)(x-5)} \\ 2x=10-4x+20\\ 6x=30\\ x= 5 [/tex]

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