jccypluv jccypluv
  • 14-05-2020
  • Mathematics
contestada

㏒₅(x+4)+㏒₅(x+1)=2 solved

Respuesta :

maggiecu
maggiecu maggiecu
  • 14-05-2020

Answer:

x= [tex]\frac{-5+\sqrt{109} }{2}[/tex]

or dec. is x= 2.72

Answer Link
Chelboy
Chelboy Chelboy
  • 14-05-2020

Answer:x=2.7 x=-7.7

Step-by-step explanation:

Log5(x+4)+Log5(x+1)=2

Log5((x+4)(x+1))=2

Log5(x^2+x+4x+4)=2

Log5(x^2+5x+4)=2

x^2+5x+4=5^2

x^2+5x+4=25

x^2+5x+4-25=0

x^2+5x-21=0

Solving the quadratic equation we get x=2.7 and -7.7

Answer Link

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