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  • 02-05-2020
  • Mathematics
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h(j) = -j^2-6j+2 when h(3)

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wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 02-05-2020

Answer:

-25

Step-by-step explanation:

h(j) = -j^2-6j+2 Let j =3

h(3) = -3^2-6(3)+2

      = -9 -18+2

     = -27+2

     = -25

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PLEASE HELP ME FACTORISE THIS ASAP! TYSM ;)–3x+2y=94x+5y=–11​