Samescharo0v8inek Samescharo0v8inek

02-08-2016
Chemistry

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suppose a 14-gram sample of iron is heated from 20.0°c to 25.0°c. the specific heat of iron is 0.11 cal/g°c. how much heat energy was absorbed by the iron?

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Willchemistry Willchemistry

08-08-2016

Q = ?

Cp = 0.11 cal/gºC

Δt = 25.0 - 20.0 => 5 ºC

m = 14 g

Q = m x Cp x Δt

Q = 14 x 0.11 x 5

Q = 7.7 cal

hope this helps!

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Аноним Аноним

04-03-2021

Answer:

Q=7.7

Explanation:

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