adrian7912 adrian7912
  • 13-03-2020
  • Mathematics
contestada

Find the zeros (x-intercepts) of the quadractic function y=2/3(3x-2)(3x+6)

Respuesta :

jimrgrant1 jimrgrant1
  • 13-03-2020

Answer:

x = - 2, x = [tex]\frac{2}{3}[/tex]

Step-by-step explanation:

T o find the zeros let y = 0, that is

[tex]\frac{2}{3}[/tex] (3x - 2)(3x + 6) = 0 ← in standard form

Equate each factor to zero and solve for x

3x - 2 = 0 ⇒ 3x = 2 ⇒ x = [tex]\frac{2}{3}[/tex]

3x + 6 = 0 ⇒ 3x = - 6 ⇒ x = - 2

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