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16-01-2020
Physics

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How much energy is needed to heat 55 Kg of water from 285 K to 360 K?

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MathPhys MathPhys

16-01-2020

Answer:

17 kJ

Explanation:

q = mCΔT

q = (55 kg) (4.184 kJ/kg/K) (360 K − 285 K)

q = 17,000 J

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