Respuesta :

Answer;

[Ba2+] = 0.550 M  

[OH-] = 1.10 M

Explanation;

Each mol Ba(OH)2 releases 2 mol OH-  

Ba(OH)2 -----> Ba2+ + 2OH-  

Mole ratio; Ba(OH)2 :Ba2+ = 1 : 1

[Ba2+] = 0.550 M  

Mole ratio; Ba(OH)2: 2OH-  = 1 : 2

= 2 × 0.550 = 1.10

[OH-] = 1.10 M  

This assumes complete ionization (dissociation) of Ba(OH)2.